Question 756543
What all this says is whenever you see {{{x}}} in {{{f(x)}}} then replace it with {{{g(x)}}}


{{{f(x)=2x+1}}} ......if {{{g(x)=(x-1)/2}}} then

{{{f(g(x))=2((x-1)/2) +1}}}

{{{f(g(x))=cross(2)((x-1)/cross(2)) +1}}}

{{{f(g(x))=(x-1) +1}}}

{{{f(g(x))=x-1 +1}}}

{{{f(g(x))=x}}}