<PRE><B>Question 756530</B>
First Number at unit place is is  x and tens place  is y 

    So original number is 10y+x 
After interchnaging digits number will be 10x+y 

 number obtained by interchanging the digits exceed the given number by 27 
    
      10y+x+27 = 10x+y
       
       10y-y+x-10+27=0

       9y-9x+27=0 

       9 (3y-3x+9=0) 

3y-3x+9=0---------(1)

       The sum of digit of a 2digit number is 9 
x+y= 9---------------(2) 

can be solved further by any method i will do by elimination method

  Multiplyinjg eq 1 by 1                          3y-3x=9
  Multiplyinjg eq 2 by 3                          3y+3x=27 
                                                                 -      -        -
                                                                       - 6x = -18 
 x= -18/-6
 x= 3
Subtituting value in  eq 1
              x+y=9
3+y=9
    y=6

 If u need it in word format let me know i have  Many sums like this solved in word 2010 that looks best thanks</PRE>