Question 756529
Suppose 1st consecutive number is x
Then second is x+2
third x+2+2 = x+4 
Fourth is x+2+2+2=x+6 
Their average is 37 

        average = total of all four numbers/ N

 37 = x+x+2+x+4+x+6/4 

 37*4= 4x+12

148=4x+12

148-12=4x

136 = 4x

136/4  = x

34= x

First number A = 34 
Third Number C= 38 
Their product = 34*38
= 1292 
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