<PRE><B>Question 755989</B>
  
tan theta = sin theta/cos theta
So 

 sin/cos=-13/12
12sin theta=-13cos theta
144sin^2theta=169^2theta
but,
    cos^2theta=1-sin^2theta
144sin^2theta=169-169sin^2theta
sin theta=169/313
sin theta=13/root313
=13root313/313 

Note: save the unrationalized denominator form for ease of taking the reciprocal later. 

Do   in the same fashion giving you three of the six functions. Then, the other functions are just reciprocals: 

  

  

  
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