Question 756428
the slope of the line thru (−3, −2) and (1, −4)is m1=[-4-(-2)]/[1-(-3)]=-2/4
                                                                       =-1/2
so the slope of the required line is m2=-1/m1=2
now the required equation of the line is [y-(-14)]/[x-(-6)]=m2=2
or [y+14]/[x+6]=2
or y+14=2[x+6]
or y-2x+2=0