Question 756387
Let x be our first odd integer, then x+2 and x+4 are the second and third consecutive odd integers.

now from the word problem we can write

3x -2 = (x+2) -2*(x+4)+16
3x -2 = x+2 -2x-8 +16
3x = x+4 -2x-8 +16
3x = -x +12
4x = 12
x=3

so our three consecutive odd integers are 3, 5, 7