Question 756266
LET f(x)=2x^3 + 3x^2 - 5x - 6 
& the zeros are a,b&c
now ab=3 given.........1
but abc=-(-6)/2=6/2=3....2[product of zeros=-(constant term )/coeff of x^3]
now from 1 & 2 
c=3/3=1= third zero