Question 65486
Subtract and express in simplest form

    3       -     1
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x^2+4x+3        x^2-9

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Factor the denominators as follows:
[3/(x+3)(x+1)]-[1/(x-3)(x+3)]
You can't do the subtraction till you get the same 
denominator on the two fractions.
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The least common denominator is (x+1)(x+3)(x-3)
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Re-write each fraction with the lcd as its denominator, as follows:
=[3(x-3)/lcd]-[(x+1)/lcd]
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Now you can perform the subraction as follows:
=[3x-9-x-1]/lcd
=[2x-10]/[(x+1)(x+3)(x-3)]
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That's as far as you can go with this messy problem.
Cheers,
Stan H.