Question 756044
The length of a rectangle is 6 more inches than its width. The area of the rectangle is 91 square inches. Find the dimensions of the rectangle.

Suppose width is x inches than length is x+6 
Area of a rectangle is=  l*b
 91=(x)*(x+6) 
 91= x^2+6x
0=x^2+6x-91
0=x^2+13x-7x-91
0=x(x+13)-7(x+13) 
0=(x-7)(x+13)
0=(x-7)        OR    0=(x+13)
7=x               OR    -13=x (negative width not possible) 
x=7 inches width and  length is six more so 7+6=13 
Answer is 7 and 13 are the length and width of the rectangle 
I hope u find my solution useful