Question 755829
Q:
A pond has 2000 fish in it due to a harmful bacteria the fish are dying at a rate of 15% per day write an equation in the form y=a(b)^t .how many fish will there be in the pond in 10 days? How long will it take for half of the fish to die?
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A:
Equation: {{{highlight(y = 2000(0.85)^t)}}}
In 10 days, there will be {{{2000(0.85^10)}}} ≈ {{{highlight(394)}}} number of fish.
{{{2000(0.85)^t = 1000}}}
{{{0.85^t}}} = {{{1/2}}}
t = {{{log(0.85, (1/2))}}} = {{{highlight(4.265)}}} days
It will take {{{highlight(4.265)}}} days for half of the fish to die.