Question 755372
{{{arctan(-3/5)=-0.54042}}} (rounded), so {{{tan(-0.54042)=-3/5}}},
but {{{-pi<-0.54042<0}}}
Since tangent has a period of {{{pi}}},
{{{tan(pi-0.54042)=-3/5}}} and {{{tan(2pi-0.54042)=-3/5}}}
so {{{highlight(x=pi-0.54042)}}} and {{{highlight(x=2pi-0.54042)}}} are solutions of {{{tan(x)=-3/5}}} and comply with {{{0<=x<2pi}}}