Question 754759
Find an equation in standard form for a hyperbola whose transverse axis endpoints are (-5,2) and (3,2) and whose conjugate axis has length 6.
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Given hyperbola has a horizontal transverse axis.
Its standard form of equation: {{{(x-h)^2/a^2-(y-k)^2/b^2=1}}}, (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (1,2)
length of horizontal transverse axis=8 (-5 to 3)=2a
a=4
a^2=16
length of conjugate axis=6=2b
b=3
b^2=9
Equation of given hyperbola:
 {{{(x-1)^2/16-(y-2)^2/9=1}}}