Question 755725
write the equation of the hyperbola with vertices at (5,0) and (-5,0) and foci at (radical 41,0) and (-radical 41,0)
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Given hyperbola has a horizontal transverse axis.
Its standard form of equation {{{(x-h)^2/a^2-(y-k)^2/b^2=1}}}, (h,k)=(x,y) coordinates of center.
center: (0,0)
a=5 (distance from center to vertices)
a^2=25
c=√41  (distance from center to foci)
c^2=41
c^2=a^2+b^2
b^2=c^2-a^2=41-25=16
Equation of given hyperbola:
 {{{x^2/25-y^2/16=1}}}