Question 755679
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Parallel lines have equal slopes.  First, determine the slope of the line comprised of the set of ordered pairs that is the solution set of the given equation.  The easiest way to do this is to solve the equation for *[tex \LARGE y] in terms of *[tex \LARGE x] and examine the coefficient on *[tex \LARGE x] that results.


Now that you have the slope of the desired line and a point on the desired line, use the point-slope form of an equation of a line to derive a form of the required equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the calculated slope.


Once you have substituted the available values, rearrange the equation into the required form, namely *[tex \LARGE ax\ +\ by\ =\ c\ \ ] where *[tex \LARGE \ \  a,\,b,\,c\ \in\ \mathbb{Z}\ \ ] and *[tex \LARGE a\ \geq\ 0], by ordinary algebraic means, i.e. adding the same quantity to both sides of the equation or multiplying both sides of the equation by the same quantity.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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