Question 755031
Find the vertex, focus and directrix of a parabola represented by the equation 
(x-3)^2=-8(y-2)
This is an equation of a parabola that opens downward.
Its basic equation: (x-h)^2=-4p(y-k)
For given equation:
vertex: (3,2)
axis of symmetry: x=3
4p=8
p=2
focus: (3,0) (p units below vertex on the axis of symmetry)
directrix: y=4 (p units above vertex on the axis of symmetry)