<PRE><B>Question 755356</B>
Let {{{ c }}} = the speed of the current
Let {{{ s }}} = the speed of the boat in still water
Let {{{ d }}} = the distance between A and B
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Boat going upriver:
{{{ d = ( s - c )*3 }}}
Boat going downriver:
{{{ d = ( s + c )*2 }}}
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By substitution:
{{{ ( s-c )*3 = ( s+c )*2 }}}
{{{ 3s - 3c = 2s + 2c }}}
{{{ s = 5c }}}
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Using substitution again:
{{{ d = ( 5c - c )*3 }}}
{{{ d = 12c }}}
and, also
{{{ d = ( 5c + c )*2 }}}
{{{ d = 12c }}}
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12 times the speed of the current is my answer
I would get a 2nd opinion on this, though


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