Question 755290
6((2y/3))-3y+2=0. 
In the brackets the external 6
is cancelled down to 2 by the 3
below the 2y. 
 3(2y) - 3y + 2 = 0
   6y - 3y + 2 = 0
Collect like terms
      3y   + 2 = 0
            3y = -2
             y = -2/3
Hope this helps.
:-)