Question 755146
Goal:  render c on one side and computable constants on the other side.


{{{10(c-6)+4=2+c-58}}}
{{{10c-60+4=2+c-58}}}
Use the additive inverse of +c.
Use the ....wait...
{{{10c-56=c-56}}} by simplifying the constants present on their sides...
Now, use the additive inverse of {{{-56}}}.
Use multiplicative inverse of {{{10}}}.
You should now have your answer.