<PRE><B>Question 754934</B>
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If you have -2 multiplicity 2, then you have two factors of *[tex \LARGE (x\ +\ 2)].  1 multiplicity 1 means you have one factor of *[tex \LARGE (x\ -\ 1)].  2 multiplicity 3 means three factors of *[tex \LARGE (x\ -\ 2)].


All together you have *[tex \LARGE f(x)\ =\ (x\ +\ 2)^2\(x\ -\ 1)(x\ -\ 2)^3]


So all you need to do is multiply it out.  Enjoy.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
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My calculator said it, I believe it, that settles it
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