Question 754917
The product of two consecutive even integers plus their sum is 98.Find the numbers.
let the two consecutive even integers are a,a+2
atq
a*(a+2)+a+(a+2)=98
or a^2+2a+2a=2=98
or a^2+4a-96=0
or a^2+12a-8a-96=0
or a(a+12)-8(a+12)=0
or (a+12)(a-8)=0
or a=-12 or 8
so the pairs of onsecutive even integers are -12 & -10 or 8 & 10