Question 65309
Ans: x can take any value because the expression is an identity.
Proof:
LHS = {{{ sin(x) + cos(x)cot(x) }}}
= {{{ sin(x) + cos(x)cos(x)/sin(x) }}}
= {{{ sin(x) + (cos(x))^2 /sin(x) }}}
= {{{ ((sin(x))^2 + (cos(x))^2)/sin(x) }}}
= {{{ 1/sin(x) }}}
= RHS