Question 754797
(X^-1y^-1)^-2 times 2x^0y^2
________________________.       All over
2x^2y^0



I came up with the answer of 1 over x^4


Sorry to say, but that's incorrect!!


{{{((x^-1y^-1)^- 2 * 2x^0y^2)/(2x^2y^0)}}}


{{{(x^(- 1 * - 2) * y^(- 1 * - 2) * 2x^0y^2)/(2x^2y^0)}}}


{{{(x^2y^2 * 2x^0y^2)/(2x^2y^0)}}}


{{{(x^2y^2 * 2(1)y^2)/(2x^2(1))}}}


{{{(2x^2y^(2 + 2))/(2x^2)}}} -------- {{{(cross(2x^2)y^4)/(cross(2x^2))}}} ----- {{{highlight_green(y^4)}}}


You can do the check!!


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