Question 754772
How to graph and find the focus of 3x^2=4y
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3(x-0)^2 = 4(y-0)
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h = 0 ; k = 0
4p = 4, so p = 1
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Plot the vertex at (0,0)
Then focus is (0,0+p) or (0,1)
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{{{graph(400,400,-10,10,-10,10,(3/4)x^2)}}}
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Cheers,
Stan H.
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