Question 65378
25X^2+10X+4 USING THE QUADRATIC EQUATION X=(-B+-SQRT[B^2-4AC])/2A WE GET
X=(-10+-SQRT10^2-4*25*4])/2*25
X=(-10+-SQRT[100-400])/50 
X=(-10+-SQRT[-300])/50
X=(-10+-[-17.32i])/50
X=-10/50-17.32i/50
X=-.2-.346i SOLUTION
X=10/50+17.32i/50
X=-.2+.346i SOLUTION
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MERRY CHRISTMAS