Question 754483
{{{X = (e^y)/(2e^y)}}}

{{{X = cross((e^y))/(2cross(e^y))}}}

{{{X = 1/2}}}

plug in {{{X = (e^y)/(2e^y)}}}

{{{1/2 = (e^y)/(2e^y)}}}....as you can see, no matter what value you choose for {{{y}}}, the result will be {{{1/2}}} because {{{e^y/e^y=1}}} as {{{(e^(-y))/(e^(-y))=1}}} as well, and if {{{y=0}}} you have {{{e^0/e^0=1/1=1}}}


so, {{{y}}} could be any value in interval ({{{-infinity}}},{{{infinity}}})