Question 754467
 "Find the largest of 3 consecutive even integers such that twice the sum of the larger two is 4 less than 5 times the smallest." I just need the equation set up for me so I can solve it.
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let x=largest of 3 consecutive even numbers
x-2=2nd largest of 3 consecutive even numbers
x-4=smallest of 3 consecutive even numbers
..
twice the sum of the larger two=2(x+x-2)
4 less than 5 times the smallest=5(x-4)-4
..
2(x+x-2)=5(x-4)-4
You can take it from here to solve for x