Question 754465
A ladder is resting against a wall making a shape of right angle triangle:

the ladder- hypotenuse {{{c}}}
the distance from the wall and the distance from the top of the ladder to the ground are legs {{{a}}} and {{{b}}}

if the distance from the top of the ladder to the ground is {{{b=10ft}}}

if the length of the ladder is two feet more than its distance from the wall, then we have {{{c=a+2ft}}}

{{{c^2=a^2+b^2}}}

{{{(a+2ft)^2=a^2+(10ft)^2}}}

{{{a^2+4aft+4ft^2=a^2+100ft^2}}}

{{{cross(a^2)+4aft+4ft^2=cross(a^2)+100ft^2}}}

{{{4aft+4ft^2=100ft^2}}}

{{{cross(4)1across(ft)=cross(100)25ft^cross(2)-cross(4)1ft^cross(2)}}}

{{{a=25ft-1ft}}}

{{{highlight(a=24ft)}}}......the distance from the wall to the bottom of the ladder 

now find  {{{c=a+2ft}}}

 {{{c=24ft+2ft}}}

 {{{highlight(c=26ft)}}}.....the length of the ladder

check:

{{{c^2=a^2+b^2}}}

{{{(26ft)^2=(24ft)^2+(10ft)^2}}}

{{{676ft^2=576ft^2+100ft^2}}}

{{{676ft^2=676ft^2}}}