Question 754320
Let theta be an angle in quadrant 3 such that the csc of theta = -6/5.
Find the exact values of the tan of theta and the cos of theta.
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use x for theta
csc x=-6/5
sin x=1/csc x=-5/6
cos x=-√1-sin^2(x)=-√(1-25/36)=-√(11/36)=-√11/6
tan x=sin x/cos x=-5/-√11=5√11/11