Question 754258
a) {{{ x(x-2)(x+5) = 0 }}}
You have 3 factors here. 

The equation is true if EITHER {{{ x = 0 }}},
or {{{ x-2 = 0 }}}, or {{{ x+5 = 0 }}}
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So, the 3 solutions are:
{{{ x = 0 }}}
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{{{ x-2 = 0 }}}
{{{ x = 2 }}}
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{{{ x + 5 = 0 }}}
{{{ x = -5 }}}
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Those are the 3 solutions