Question 753489
2x^2= 8x - 6
2x^2 - 8x + 6
(2x - 2)(x - 3)
 x = 1, 3
Integrate 2x^2 - 8x + 6
         [ 2x^3/3 - 4x^2 + 6x]
Using x=1 and x = 3
       (2*3^3/3 - 4*3^2 + 6*3)-(2*1^3/3 - 4*1^2 + 6*1)

        (54/3 - 36 + 18) - (2/3 - 4 + 6)

         (54/3 - 54/3) - (2/3 + 6/3)
                       - 8/3 units^2