Question 753674
Drawing (not to scale):
{{{drawing(500,300,-0.5,4.5,-0.5,2.5,
green(line(-0.5,0,4.5,0)),
red(line(4,0,4,2.5)),
triangle(0,0,4,0,4,2),
line(1,0,1,0.5),
locate(0.4,0.15,440m),locate(2,0.15,3200m),
locate(1.01,0.4,x),locate(3.65,1.1,330m),
locate(-0.05,0,C),locate(0.95,0,B),locate(3.95,0,E),
locate(0.95,0.7,A),locate(4.05,2.1,D),locate(4.05,2.5,red(tower))
)}}} The camera is at C, lined up with smokestack AB and the tower (red), all on the vertical plane of the drawing.
Triangles ABC and DEC are similar (same angle measures, proportional side lengths, ABC is a scaled down version of DEC).
So {{{x/440=330/(440+3200)}}} --> {{{x/440=330/3640}}} --> {{{x=330*440/3640}}} --> {{{highlight(x=40)}}} (rounded)
The smokestack's height is approximately {{{highlight(40meters)}}}