Question 753764
    a biology class has 8 students. how many different lab groups may be formed that will consist of 3 students?
.
since order does not matter, it is a combination:
8C3
= (8!)/[3!(8-3)!]
= (8!)/[3!5!]
= (6*7*8)/[3!]
= (6*7*8)/[2*3]
= (2*7*8)/[2]
= (7*8)
= 56