Question 753750
(percent mixture wanted) = (amount of pure drug)/(mixture)


Amount of just the drug is {{{0.16*x+0.28*y}}}
Amount of mixture obviously was given, 15 ml.
This uses x for amount of the 16 drug and y for the amount of the 28% drug.


The FRACTION of the mixture as drug we want is 0.24, which means same as 24%.


Put everything in place:
{{{(0.16x+0.28y)/15=0.24}}}  AND {{{x+y=15}}}
Solving this system should not be any trouble.