Question 753706

to find the slope and the {{{y-intercept}}} you first need to write your equation in slope-intercept form {{{y=mx+b}}} where {{{m}}} is the slope and {{{b}}} is the {{{y-intercept}}}


{{{x+4y=8}}}....so, solve for {{{y}}}

{{{4y=-x+8}}}

{{{y=-x/4+8/4}}}

{{{y=-(1/4)x+2}}}

so, the slope is {{{m=-(1/4)}}} and  the {{{y-intercept}}} is {{{b=2}}}, in other words the line intersects {{{y-axis}}} at ({{{0}}},{{{2}}})  

to find the {{{x-intercept}}} set {{{y=0}}} and solve for {{{x}}}

{{{x+4*0=8}}}

{{{x=8}}}...so, the line intersects {{{x-axis}}} at ({{{8}}},{{{0}}})


{{{ graph( 600, 600, -10,10, -10, 10, -(1/4)x+2) }}}