<PRE><B>Question 753721</B>
Two cyclists start at the same point and travel in opposite directions. 
One travels 5 mph faster than the other. 
In 6 hours they are 594 miles apart. 
Find how fast each is traveling.
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slower cyclist DATA: rate =  x mph ; time = 6 hrs ; distance = rt= 6x miles
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faster cyclist DATA: rate = x+5 mph ; time = 6 hrs ; distance 6(x+5) miles
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Equation:
6x + 6x+30 = 594
12x = 564
x = 47 mph (slower cyclist rate)
x+5 = 52 mph (faster cyclist rate)
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Cheers,
Stan H.
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