<PRE><B>Question 753722</B>
solve for x

12000(1-0.06)^x=8000
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(1-0.06)^x=8000/12000 = 2/3
{{{0.94^x = 2/3}}}
x*log(0.94) = log(2/3)
x = log(2/3)/log(0.94)
Was that hard?

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