Question 753694
The x-intercepts of the graph are (3,0) ,(2,0) and 
(8,0). The y-intercept is (0,1). However the given graph is a 4th degree polynomial function pointing down.
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Comment: One of those x-intercepts must have multiplicity 2.
Since the function is 4th degree and opens down I think the
(3,0) must have multiplicty 2.
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If so, you get:
f(x) = a(x-2)(x-3)^2(x-8)
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Since f(0) = 1, solve for "a":
f(0) = a(-2)(-3)^2(-8) = 1
a*16*9 = 1
a = 1/144
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Equation:
f(x) = (1/144)(x-2)(x-3)^2(x-8)
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Cheers,
Stan H.