Question 753662
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There is no such thing as a hypot<i><b>i</b></i>nuse.  The side opposite the right angle in a right triangle is a hypot<i><b>e</b></i>nuse.  You probably misspelled it because you are mispronouncing it.  h&#299;-&#712;pä-t&#601;-&#716;nüs NOT  h&#299;-&#712;pä-tin-&#716;üs


The sine is the opposite divided by the hypotenuse


The cosine is the adjacent divided by the hypotenuse


The tangent is the sine divided by the cosine which reduces to the opposite divided by the adjacent


The cotangent is the reciprocal of tangent


The secant is the reciprocal of cosine


The cosecant is the reciprocal of sine


Use Pythagoras to find the measure of the missing side in your second problem.  Leave the value in radical form, but remember to rationalize your denominators when you calculate the trig functions.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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