<PRE><B>Question 753672</B>
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ c(x)\ =\ x^2\ +\ 6x\ +\ 14]


Divide the coefficient on the first degree term by 2.  (6 over 2 is 3) Square the result. (3 squared is 9)  Add that result (9) and the opposite of that result (-9) to the RHS of the equation.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ c(x)\ =\ x^2\ +\ 6x\ +\ 9\ +\ 14\ -\ 9]


Factor the perfect square trinomial and simplify the remainder of the RHS:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ c(x) = (x\ +\ 3)^2\ +\ 5]


Done.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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