<PRE><B>Question 6918</B>
bonster(299)&#39;s answer is incorrect.


The field is 360 feet long  by 150 feet wide, and the fence is being placed 60 feet from EACH end zone and 45 from EACH sideline.  Therefore, the solution is;

P=l+w+l+w or 2l +2w

P=(60+360+60)+(45+150+45)+(60+360+60)+(45+150+45)
P = 2*(480)+ 2*(240)
P = 960 + 480
P = 1440

1440 feet of fence will be needed.

The key is adding the additional fence on both ends.</PRE>