Question 753422
Lisa has 9 rings in her jewelry box. 5 are gold and 4 are silver. If she randomly selects 3 rings to wear to a party,find each probability. 
14. P ( all gold or all silver) 
and 16: P( at least 1 silver) 

14) what is P for all gold or all silver
    P for all gold
    first ring is gold, P is 5/9
    second ring is gold, P is 4/8
    third ring is gold, P is 3/7
    P for all gold is (5/9)*(4/8)*(3/7)=.12 or 12%
    P for all silver
    first ring is silver, P is 4/9
    second ring is silver, P is 3/8
    third ring is silver, P is 2/7
    P for all silver is (4/9)*(3/8)*(2/7)=.05 or 5%

16) P at least 1 is silver has the following possibilities, note that the probability of 1 silver is 4/9 and probability of 1 gold is 5/9
    SGG = (4/9)(5/9)^2 = .14
    GSG = (5/9)^2(4/9) = .14
    GGS = (5/9)^2(4/9) = .14
    SSG = (4/9)^2(5/9) = .11
    SGS = (4/9)^2(5/9) = .11
    GSS = (4/9)^2(5/9) = .11
    SSS = (4/9)^3      = .09

now add all 7 probabilities and our answer is .84 or 84%