Question 753399

let the first number be {{{x}}}
if he second of two numbers {{{y}}} is {{{5}}} more than twice the first, then

{{{y=2x+5}}}

if  their sum is {{{80}}}, then

{{{x+y=80}}}.....substitute {{{y}}}

{{{x+2x+5=80}}}...solve for {{{x}}}

{{{3x=80-5}}}

{{{3x=75}}}

{{{x=75/3}}}

{{{highlight(x=25)}}}

now find {{{y}}}

{{{y=2x+5}}}

{{{y=2*25+5}}}

{{{y=50+5}}}

{{{highlight(y=55)}}}