Question 753365
Hello, 
This t^2 + 3 = 6t will require the quadratic formula but first let's rewrite this as:
t^2 -6t + 3 = 0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
Plug in the values:
{{{x = (6 +- sqrt( 6^2-4*1*3 ))/(2*1) }}}
Simplifiy to:
x = 6 +- sqrt (24)/2 rewritten as:
x= 6 +- 2 sqrt 6/2 or 
x = 3 +- sqrt 6
make sense?
RJ
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