Question 753059

I've been stuck on this problem since Friday. Help please.  

The length of a rectangle is 4 inches shorter than twice the width. If the perimeter of the rectangle is 34 inches, find the length and the width of the triangle.

The answer on the paper is L=10 W=7


Let width be W
Then length = 2W - 4


Since perimeter = 34, then 2L + 2W = 34 ----- 2(L + W) = 2(17) ----- L + W = 17


Since L = 2W - 4, then L + W = 17  becomes: 2W - 4 + W = 17


3W = 17 + 4


3W = 21


W, or width = {{{21/3}}}, or {{{highlight_green(7)}}} inches


Substituting 7 for W, L or length = 2(7) - 4, or {{{highlight_green(10)}}} inches 


You can do the check!!


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