Question 753012
Give the equation, in polynomial form, of the circle if (-17,7) and (13,-9) are endpoints of a diameter of the circle.
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The midpoint of that diameter is (x,y)
where
x = (13-17)/2 = -2
y = (7-9)/2 = -1
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So the center of the circle is (-2,-1)
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radius = distance from (-2,-1) to (13,-9)
= sqrt[(-9--2)^2 + (13--2)^2]
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= sqrt[7^2 + 15^2]
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= sqrt[274] 
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Equation: (x-2)^2 + (y+1)^2 = 274
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Cheers,
Stan H.
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