Question 752890
given:
 the vertex ({{{0}}},{{{0}}}) and a focus ({{{0}}},{{{-1/12}}})

The directed distance from the vertex to the focus is called {{{p}}}, the "parabolic constant".  If going from vertex to focus is an upward or rightward motion, then {{{ p}}} is positive.  If downward  or leftward, then {{{p }}} is negative.  Here {{{p}}} is negative, in fact,it is {{{-1/12}}} because going from the vertex ({{{0}}},{{{0}}}) to the focus.

The value of {{{p}}} is  {{{-1/12}}}, since that is the directed distance from the vertex to the focus. Since the axis is vertical, the general equation is  

{{{y= 4px^2 }}}

 So your equation is :

{{{y = 4( -1/12)x^2 }}}

{{{y =-3x^2 }}}


{{{ graph( 600,600, -5, 5, -10, 5, -3x^2)) }}}