Question 752775
solve equation 9^(x+3)=3^(4x-2)
We know that 9 = 3^2, therefore we can write the equation as
{{{3^(2(x+3))}}} = {{{3^((4x-2))}}}
When the numbers are equal, the exponents are equal, so we have:
2(x+3) = 4x -2
2x + 6 = 4x - 2
6 + 2 = 4x - 2x
8 = 2x
x = 8/2
x = 4