Question 752582
Determine the equation of the line with slope -2/3 and passes through
 the point (-6, 3).
Express the equation of the line in both slope–intercept form
:
Use the point point/slope formula: y - y1 = m(x - x1)
y - 3 = {{{-2/3}}}(x - (-6))
y - 3 = {{{-2/3}}}(x + 6)
y - 3 = {{{-2/3}}}x - 4
y = {{{-2/3}}}x - 4 + 3
y = {{{-2/3}}}x - 1; the slope/intercept form
:
Find the standard form
y = {{{-2/3}}}x - 1
{{{2/3}}}x + y - 1
get rid of the denominator, mult by 3, resulting in:
2x + 3y = -3
:
:
Check solutions by replacing x and y with -6 and 3
2(-6) + 3(3) = -3