Question 752747
Find the equation of the parabola with Y intercept (0,6) and the vertex is (2,8). These are the only points given. 

The vertex form of a quadratic function is
y=a(x−h)^2 + k
where (h,k) is the vertex. Use your given vertex, and solve for a using the fact that you know the y-intercept.

Note that the vertex and any other point on the curve would be sufficient.

y = a(x-2)^2 + 8

6 = a(0-2)^2 + 8
6 = 4a + 8
4a = -2
a = -1/2

y = (-1/2)(x-2)^2 + 8