<PRE><B>Question 752614</B>
Find z, if the probability that a random variable having the standard normal distribution will take on a value.
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Using a TI-84:
(i) less than z is 0.9911 = invNorm(0.9911) = 2.3698
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(ii) greater than z is 0.1093 = normalcdf(0.1093,100) = 0.4565
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(iii) beteen -z and z is 0.9298
Draw the picture on a standard normal curve.
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The area is split into two equal parts; each is (1/2)0.9298 = 0.4649
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The left tail for -z is (0.5-0.4649) = 0.0351
That negative z-value is invNorm(0.0351) = -1.8106
z = +1.8106
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Cheers,
Stan H.
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